In this example you get the result c = x^3, so that is the case. If your expression ( a + b) has a value that is constant over the solution set of the condition, and if Mathematica is able to simplify it, then you'll get a result that is independent of any of the variables in the expression ( a and b). Substitute either of these into the condition, a^3 + 3 a^2 b + 3 a b^2 + b^3 = c /. Solve the equation a + b = x for either a or b, giving a = x - b or b = x - a.The equations are written in the form of lefthandside righthandside. Its syntax is Solve eqns, vars, where eqns is your equation or set of equations and vars are the variable (s) in the equation (s). Mathematica 2D Heat Equation Search: Examples Of 2d Heat Equation.
What you can do sometimes is this: introduce a new variable to represent the value of your expression, solve the resulting equation for one of the original variables (perhaps manually), then substitute it into the condition. Solve is the Mathematica function used for symbolically solving a polynomial equation or set of equations. The key problem is that I have some trouble in solving the equation A python model of. In general, that's not possible - that is, for an arbitrary expression subject to an arbitrary constraint, there's no guarantee that the expression will have the same value at all the points satisfied by the constraint. But I'm guessing that what you meant to ask was how you can find the value of an expression ( a+b) subject to a constraining equation ( a^3 + 3 a^2 b + 3 a b^2 + b^3 = c). As pointed out in the comments, you can't solve an expression.
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